regex - How do I replace a newline in Atom? -


in atom, if activate regex mode on search-and-replace tool, can find newlines \n, when try replace them, they're still there.

is there no way replace newline-spanning string in atom?

looks atom matches newlines \r\n behaves inconsistently when replacing \n nothing.

so newlines seem match \s+ , \r\n, , "half" of line-ending matches \n.

  • if replace \n string, nothing happens line-ending, string appended next line
  • if replace \r string, nothing happens @ all, cursor advances.

Comments

Post a Comment

Popular posts from this blog

user interface - how to replace an ongoing process of image capture from another process call over the same ImageLabel in python's GUI TKinter -

i trying use following code create interactive gui changes color-space(hsv, rbg, grayscale etc) on event of button click. display opencv video in tkinter using multiprocessing being new python having problems multiprocessing , attempts on making gui change it's color space on button clicks hangs entire system. on it's implementation highly appreciated. thankyou. below code: import cv2 pil import image,imagetk import tkinter tk import numpy np multiprocessing import process , queue def quit_it(root,process): root.destroy() process.terminate() def black_andwhite(root,process): process.terminate p=process(target=capture_image, args=(5,queue, )) p.start() root.after(0, func=lambda: update_all(root, image_label, queue)) def update_image(image_label, queue): frame = queue.get() = image.fromarray(frame) b = imagetk.photoimage(image=a) image_label.configure(image=b) image_label._image_cache = b root.update() def update_all(root...
Read more

javascript - Restarting Supervisor and effect on FlaskSocketIO -

in index.html (html/javascript) have: $(document).ready(function(){ namespace = '/test'; var socket = io.connect('http://' + document.domain + ':' + location.port + namespace); socket.on('connect', function() { socket.emit('join', {room: 'venue_1'}); }); socket.on('my response', function(msg) { $('#log').append('<br>received #' + ': ' + msg.data); }); }); on server have: @socketio.on('connect', namespace='/test') def test_connect(): if session.get('venue_id'): emit('my response', {'data': 'connected'}) session.pop('venue_id', none) else: request.namespace.disconnect() @socketio.on('join', namespace='/test') def join(message): join_room(message['room']) room = message[...
Read more

android - Format a french phone number -

i have format "0612345678" "06 12 34 56 78". i'm using : private string formattel(string number) { try { string formattednumber = ""; int i; (i = 0; < 10; += 2) { formattednumber += number.substring(i, + 2) + " "; } return formattednumber.substring(0, formattednumber.length() - 1); } catch (indexoutofboundsexception e) { return number; } } it works on emulator running api 16 (jellybean 4.1.1) : on it, result looks want ("06 12 34 56 78") on own phone, (api 22, lollipop 5.1.1), doesn't work : result "0 61 23 45 67" whereas method same ! i did research , i've found string.format method. it's here need help, it's hard me... ! thank in advance :d edit : working method, using libphonenumber : private string formattel(string number) { string formattednumber = number; try { phonenumberutil phonenumberutil = ph...
Read more