bash - extract data date wise and do average calculation -


how extract data date wise , average calculation per date below shown output. last column average.

sun jul  5 00:00:02 ist 2015, 97 sun jul  5 00:02:01 ist 2015, 97 sun jul  5 00:04:02 ist 2015, 97 mon jul  6 00:00:01 ist 2015, 73 mon jul  6 00:02:02 ist 2015, 93 mon jul  6 00:04:02 ist 2015, 97 tue jul  7 00:00:02 ist 2015, 97 tue jul  7 00:02:02 ist 2015, 97 tue jul  7 00:04:01 ist 2015, 97 wed jul  8 00:00:01 ist 2015, 98 wed jul  8 00:02:02 ist 2015, 98 wed jul  8 00:04:01 ist 2015, 98 thu jul  9 00:00:02 ist 2015, 100 thu jul  9 00:02:01 ist 2015, 100 thu jul  9 00:04:01 ist 2015, 100 fri jul 10 00:00:01 ist 2015, 100 fri jul 10 00:02:02 ist 2015, 100 fri jul 10 00:04:02 ist 2015, 100 sat jul 11 00:00:01 ist 2015, 73 sat jul 11 00:02:01 ist 2015, 73 sat jul 11 00:04:02 ist 2015, 73

want output 

jun  6 - 97 jun  7 - 86.66 ...

you can use awk:

awk -f ', ' '{    split($1, a, " ");    k=a[2] ofs a[3];    if(!(k in c))       b[++n]=k;    c[k]++;    sum[k]+=$2 } end{    for(i=1; i<=n; i++)       printf "%s - %.2f\n", b[i], (sum[b[i]]/c[b[i]]) }' file jul 5 - 97.00 jul 6 - 87.67 jul 7 - 97.00 jul 8 - 98.00 jul 9 - 100.00 jul 10 - 100.00 jul 11 - 73.00

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