excel - VBA If a specific cell in Sheet1 contains data > 0, put a specific code on Sheet2 -
i'm given set of data on sheet1 may this:
b c d e f g h (codes) 31 21957 0 3707 0 1996 356 3422 32 13 0 13 0 13 10 3455 33 4543 0 767 0 413 423 3446 34 6119 0 1033 0 556 1549 3603 35 12238 0 2066 0 1113 56 3703 each row of data corresponds code (see codes column above). example, data in row 31 greater 0 has code 34-22. row 32 34-55, row 33 34-46, row 34 36-03, , row 35 37-03.
how can write macro can have result on sheet2 based on data above:
ag ah ai aj 57 3 4 2 2 (based on data in cell b31 of sheet1) 58 3 4 5 5 (based on data in cell b32 of sheet1) 59 3 4 4 6 (based on data in cell b33 of sheet1) 60 3 6 0 3 (based on data in cell b34 of sheet1) 61 3 7 0 3 (based on data in cell b35 of sheet1) 62 3 4 2 2 (based on data in cell d31 of sheet1) 63 3 4 5 5 (based on data in cell d32 of sheet1) and on , forth...
so far, have this:
dim x integer, destlast long, holdval string if sheets("sheet1").range("b31").value > 0 destlast = sheets("sheet2").range("ag" & rows.count).end(xlup).row + 1 if destlast < 57 destlast = 57 holdval = sheets("sheet1").range("h31").value x = 1 4 dim columnnumber2 integer columnnumber2 = 32 + x sheets("sheet2").cells(destlast, columnnumber2).value = mid(holdval, x, 1) next x end if the problem have write macro every cell (b31:g35). there easier way of doing this?
please let me know if i'm missing information or if have questions i'm asking!
something (not tested -- i'm taking granted body of loop, wrote, want cell b31 , illustrating how modify apply entire range of cells, in column column manner seem want)
dim long, j long j = 2 7 'columns b g = 31 35 if sheets("sheet1").cells(i,j).value > 0 destlast = sheets("sheet2").range("ag" & rows.count).end(xlup).row + 1 if destlast < 57 destlast = 57 holdval = trim(str(sheets("sheet1").cells(i,8).value)) x = 1 4 dim columnnumber2 integer columnnumber2 = 32 + x sheets("sheet2").cells(destlast, columnnumber2).value = mid(holdval, x, 1) next x end if next next j
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