Python parsedatetime: get current month / first of the month -


i'm using parsedatetime library in python script , appears "last month" works , "next month" not "this month."

what missing? there way first day of current month?

edit: sorry, here's code:

import parsedatetime.parsedatetime pdt p = pdt.calendar() res = p.parse('this month') print(str(res))

returns:

(time.struct_time(tm_year=2015, tm_mon=7, tm_mday=13, tm_hour=16, tm_min=22, tm_sec=10, tm_wday=0, tm_yday=194, tm_isdst=0), 0)

i've never used parsedatetime though that's interesting way first of month. still, this:

>>> datetime.datetime.now().replace(day=1, hour=0, minute=0, second=0)

it's less wasteful of resources, too, since don't have parse text @ runtime, that's aside, really.

you can convert time.struct_time via timetuple():

>>> datetime.datetime.now().replace(day=1, hour=0, minute=0, second=0).timetuple()

time.struct_time(tm_year=2015, tm_mon=7, tm_mday=1, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=2, tm_yday=182, tm_isdst=-1)


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