c# - How to change the 'object sender'? -

i create datagridview in makedatagridview function, , maybe datagridview rightclick -> appear context menu

this sample code

public void click(object sender, mouseeventargs e) {         if(e.button == mousebuttons.right) {                contextmenustrip menu = new contextmenustrip();                toolstripitem insert = menu.items.add("insert");                insert.click += new eventhandler(context_menu_click);         } }  public void context_menu_click(object sender, eventargs e) {         / *            other event ,            printing .txt file datagridview         */ } 

i want print .txt file datagridview in 'context_menu_click' function. sender of click function datagridview, context_menu_click sender toolstripmenu.

so, how can print .txt file datagridview in context_menu_click function?

public void context_menu_click(object sender, eventargs e) {     /*         other event ,         printing .txt file datagridview     */     var item = sender toolstripitem  ;     if (item != null)     {         datagridview gv = item.tag datagridview;         console.writeline(gv.name);     } } private void datagridview1_mouseclick(object sender, mouseeventargs e) {     if (e.button == mousebuttons.right)     {         contextmenustrip menu = new contextmenustrip();         toolstripitem insert = menu.items.add("insert");         insert.tag = sender;         insert.click += new eventhandler(context_menu_click);         menu.show(this.datagridview1.pointtoscreen(new point(e.x, e.y)));     } } 

you can add current datagridview tag toolstripitem create