BASH - find regex in array, print found array items -


i have tested regex here: http://regexr.com/3bchs

i cant array print regex search terms.

files=(`ls $backupdir`) daterange='(2015\-06\-)[0-9]+\s?'  in "${files[@]}"         if [[ "$files[$i]" =~ $daterange ]];                           echo $i          fi done

input: 2015-06-06 2015-06-13 2015-06-20 2015-06-27 2015-07-04 2015-07-11

output:

2015-06-06  2015-06-13  2015-06-20  2015-06-27  2015-07-04  2015-07-11

by running bash -vx <script> found out files compering wrong. needed change $files[$i] $i.

$files[$i] = 2015-06-06[2015-06-06]

i have further improved answer etan reisner comment. not parsing output ls.

reference: https://stackoverflow.com/a/11584156/3371795

#!/bin/bash  # enable special handling prevent expansion # literal '/example/backups/*' when no matches found.  shopt -s nullglob          # variables         year=`date +%y`         month=`date +%m`          dir=(/home/user/backups/backup.weekly/*)          # regex - curent month         date_range='('$year'\-'$month'\-)[0-9]+\s?'   # loop through dir in "${dir[@]}";         # compare dir name date range         if [[ "$i" =~ $date_range ]];                         # have no idea is, works fine without it.                 [[ -d "$i" ]]                   # echo found dirs                 echo "$i"         fi done

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