matlab - Find overlapping between two lists in c# -


i have got matlab code calculates overlap of 2 lists. in fact check if list h inside list u , keeps window of list u list h inside(at least 1 time). in fact u, h index list of nx2 size in every point there 2 values begining index of window , end index of window. code in matlab is:

function w = getwindowsspecial(u,h) w = []; = 1:size(u,1)   if any(h(:,1)>=u(i,1) & h(:,1)<=u(i,2))     w = [w;u(i,:)];   end end 

for example u be:

54  86 112 217 292 325 402 451 628 664 

h be:

129 214 297 321 406 447 637 664 

and result w is:

112 217 292 325 402 451 

i want convert code c#. list u, h list>>. correspondant function following:

 static list<int> getwindows(list<list<int>> list1, list<list<int>> list2)     {         list<int> list3 = new list<int>();          (int index = 0; index < list1[0].count; index++) {           }              return list3;     } 

what should fill in function in order work matlab one?

edit: in code add limits first , second list. how possible add limits tuple instead of list of lists?

        list<list<int>> first = new list<list<int>>();         list<list<int>> second = new list<list<int>>();         first.add(upfirst); first.add(downfirst);         second.add(upsecond); second.add(downsecond);          getwindows(first, second); 

upfirst , upsecond contains left limits first , second list , downfirst , downsecond contains right limits first , second lists. tried use following code job:

 (int index = 0; index < upfirst.count; index++){              first.add(new list<int> { upfirst[index], downfirst[index] });   }   (int index = 0; index < upsecond.count; index++){             second.add(new list<int> { upsecond[index], downsecond[index]});    }   list<list<int>> lista = getwindows(first, second); 

this tried in order add tuples. using function of @m. nasser javaid got null result. input provide list of lists first , second are:enter image description here

try please. according given scenario need numbers u in range of h are...

public void test()     {         var listu = new list<list<int>>         {             new list<int> {54, 86},             new list<int> {112, 217},             new list<int> {292, 325},             new list<int> {402, 451},             new list<int> {628, 664}         };         var listh = new list<list<int>>         {             new list<int> {129, 214},             new list<int> {297, 321},             new list<int> {406, 447},             new list<int> {637, 664}         };         getwindows(listu, listh);     }  static list<list<int>> getwindows(list<list<int>> listu, list<list<int>> listh)     {         list<list<int>> list3 = new list<list<int>>();         var startingofh = listh.first()[0];         var endofh = listh.last()[listh.last().count - 1];         foreach (var num in listu)         {             var initial = num[0];             var final = num[num.count - 1];             if (initial > startingofh && final < endofh)             {                 list3.add(num);             }         }         return list3;     } 

edit: if want use linq use this

static list<list<int>> getwindows(list<list<int>> listu, list<list<int>> listh)     {         var startingofh = listh.first()[0];         var endofh = listh.last()[listh.last().count - 1];         return (from num in listu                  let initial = num[0]                  let final = num[num.count - 1]                  initial > startingofh && final < endofh                  select num).tolist();     } 

edit 2: ignore initial value

static list<list<int>> getwindows(list<list<int>> listu, list<list<int>> listh)     {         list<list<int>> list3 = new list<list<int>>();         var startingofh = listh.first()[0];         var endofh = listh.last()[listh.last().count - 1];         foreach (var num in listh)         {             var final = num[num.count - 1];             if (final > startingofh && final < endofh)             {                 list3.add(num);             }         }         return list3;     } 

if linq

static list<list<int>> getwindows(list<list<int>> listu, list<list<int>> listh)     {         var startingofh = listh.first()[0];         var endofh = listh.last()[listh.last().count - 1];         return (from num in listh                  let final = num[num.count - 1]                  final > startingofh && final < endofh                  select num).tolist();     } 

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