Extracting vectors from list in R without looping -


this simple question, have googled hours without satisfying answer. let's suppose have list following one:

thelist <- list(c("de", "labore", "solis"), c("sapiento", "post", "eventum"), c("sursum", "corda"))  > thelist [[1]] [1] "de"     "labore" "solis"   [[2]] [1] "sapiento" "post"     "eventum"   [[3]] [1] "sursum" "corda"

if want print vectors compose list think of like

for(i in 1:length(thelist)) {   print(thelist[[i]]) }  [1] "de"     "labore" "solis"  [1] "sapiento" "post"     "eventum"  [1] "sursum" "corda"

however there must more elegant solution, using member of apply family...

i think got answer after doing more googling , experimenting...

extract <- function(m) {   sapply(seq_along(m), function(x) m[[x]]) }  > extract(thelist) [[1]] [1] "de"     "labore" "solis"   [[2]] [1] "sapiento" "post"     "eventum"   [[3]] [1] "sursum" "corda"

so matter of performing desired operation (e.g. printing) on result sapply


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