unix - Bash Script: want to call a function that reads input -

i'm writing script calls on function reads input in multiple lines. want pass parameters read, don't know if can or how to.

aka how enter-grades take values input instead of waiting input @ prompts?

inside bash script

... login="studentname" echo "enter score:" read score  echo "comments:" read comments enter-grades $hw #---> calls function (dont know definition) # # want pass parameters enter-grades each read echo "$login" #---> input enter-grade's first read echo "$score $comments" #---> input enter-grade's second read echo "." #---> input enter-grade's third read 

outside bash script

#calling enter-grades > enter-grades hw2 entering grades assignment hw2. reading previous scores hw2... done. enter grades 1 @ time.  end login of '.' login: [reads input here] grade , comments: [reads input here] login: [reads input here] 

assuming enter-grades not read directly terminal, supply information on program's standard input:

login="studentname" read -p "enter score: " score  read -p "comments: " comments 

then, group echo commands together, , pass program:

{     echo "$login"     echo "$score $comments"     echo "." } | enter-grades "$hw" 

or, succinctly

printf "%s\n" "$login" "$score $comments" "." | enter-grades "$hw" 

quote all variables.

or, here-doc

enter-grades "$hw" <<end $login $score $comments . end