java - Compare two List<E> regardless of order -


i have 2 e type lists list list1, list list2. e object pojo class contains row of following data. both of lists contain same data. example @ last column if change false true cannot detect.

| statusid  | statusname                                | statusstate | isrequire            | | 3         | approved                                  | approved    | false                | | 201       | attributed                                | rejected    | true                 | | 202       | denied                                    | rejected    | false                | | 204       | fraud                                     | rejected    | false                | | 205       | insufficient                              | rejected    | false                | | 206       | invalid                                   | rejected    | false                | | 207       | cancelled                                 | rejected    | false                | | 208       | cannot traced                             | rejected    | false                | | 209       | transaction online                        | rejected    | false                | | 210       | voucher                                   | rejected    | false                | | 211       | not meet req                         | rejected    | false                |

i want write function if data 2 lists different can detectected. following code seems give 'false' whether data same or different in both lists.

   private boolean comparelists(list<status> actualstatuses, list<status> expectedstatuses) {     boolean indicator = false;     if (actualstatuses!= null && expectedstatuses!=null && actualstatuses.size() == expectedstatuses.size()){         (status expectedstatusdata : expectedstatuses){             for(status actualstatusdata : actualstatuses){                 if(actualstatusdata.getstatusid() == expectedstatusdata.getstatusid()                         && actualstatusdata.getstatusname().equals(expectedstatusdata.getstatusname())                         && actualstatusdata.getstatusstate().equals(expectedstatusdata.getstatusstate())                         && actualstatusdata.isenable() == expectedstatusdata.isenable()                         && actualclaimstatusdata.isrequire() == expectedstatusdata.isrequire()){                     indicator = true;                     break;                 }                 else indicator = false;             }         }         if (indicator)             return true;     }     else         return false;      return indicator; }

a better way of doing (assuming list doesn't contain repeated values) store elements of 1 list in hashset , check if hashset contains of elements of other list , sizes same.

private <e> boolean listshavesameelements(final list<e> l1, final list<e> l2) {     final set<e> set = new hashset<>(l1);     return l1.size() == l2.size() && set.containsall(l2); }

this o(n+m) solution while using list.containsall() need iterate elements of other list check existence o(n*m)


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