scala - Partioning a List into more than two partitions -


i have list:

val list1 = list("male:adam", "male:peter", "female:jane", "female:sue", "female:jo", "other:john")

i want create 2 lists, 1 of female names , 1 of male names. i.e.:

list("adam", "peter") list("jane", "sue", "jo")

i've done 

val result = list1.groupby(_.startswith("male"))

so result has 2 lists mapped against true , false each element being "male:adam" etc. i'd have cycle through each list removing male: , female: strings. smells of non-functional.

can show how above problem solved in functional way?

val map = list1.map(s => s.split(":") match {    case array(sex, name) => (sex, name)  }) .groupby { case (sex, name) => sex } .mapvalues(_.map{ case (sex, name) => name })  val male = map("male") // list(adam, peter) val female = map("female") // list(jane, sue, jo)

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