How does c compare character variable against string? -

the following code ok in c not in c++. in following code if statement false. how c compares character variable against string?

int main() {   char ch='a';   if(ch=="a")     printf("confusion");   return 0; }

the following code ok in c

no, not @ all.

in code

  if(ch=="a")

is trying compare value of ch base address of string literal "a",. meaning-and-use-less.

what want here, use single quotes (') denote char literal, like

  if(ch == 'a')

note 1:

to elaborate on difference between single quotes char literals , double quotes string literal s,

for char literal, c11, chapter §6.4.4.4

an integer character constant sequence of 1 or more multibyte characters enclosed in single-quotes, in 'x'

and, string literal, chapter §6.4.5

acharacter string literal sequence of 0 or more multibyte characters enclosed in double-quotes, in "xyz".

note 2:

that said, note, recommend signature of main() int main(void).

Brant