mysql - Select * from table where id = ? and order by priority -


i have database fields:

  • id (int)
  • name (text)
  • priority (int)

i want show values database id = (e.g) 13 , sort them priority. e.g: field id 13 , priority 1 first other field priority 2.

how can it?

select id,name,priority table_name id=13 order priority asc;

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