ruby - Alphabetize a list by the nth character -


write function accepts 2 parameters, i) string (containing list of words) , ii) integer (n). function should alphabetize list based on nth letter of each word.

i have tried

def sort_it(list_, n)   list_.sort_by {|name| name[n]} end

but saying sort_by not recognised.

is there elegant way solve this?

list_ string while sort_by method of enumerable. need convert string collection of words before sorting. 1 way is

list_.split

so code 

def sort_it(list_, n)   list_.split.sort_by {|name| name[n]} end

as side note, don't use trailing underscore in argument name.


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